If we subtract the mass of carbon dioxide from the total mass of the reactants, we can determine the mass of the residue, which is basically a sodium acetate solution. The total mass of the products must equal the mass of the reactants. The reactants are 8.4 g sodium bicarbonate and 20 g acetic acid solution.
#"NaHCO"_3 + "CH"_3"COOH"#rarr#"CH"_3"COONa + CO"_2 + "H"_2"O"#Īccording to the law of conservation of mass, the total mass of the reactants equals the total mass of the products. The carbon dioxide bubbles out of solution, leaving behind a sodium acetate solution. In this reaction, sodium bicarbonate reacts with acetic acid to produce sodium acetate, carbon dioxide, and water. The mass of the residue, or sodium acetate solution, should be #"24.0 g"# of sodium acetate solution. Material Qualification Dossier Quality Management Dossier SDS CoA Certificates Synonyms: Acetic acid sodium salt CAS : 127-09-3 EC Number: 204-823-8 Molar Mass: 82. #m_"residue" = m_"products" - m_(CO_2) = 14.4 - 4.4 = "10.0 g"# Sodium acetate MSDS (material safety data sheet) or SDS, CoA and CoQ, dossiers, brochures and other available documents. When sodium acetate is severely heated with soda lime, which is a combination of sodium hydroxide (NaOH) and calcium oxide (CaO) in a 3:1 mass ratio, methane is generated as a result. #m_"products" = m_"reactants" = "14.4 g"# Molecular Weight/ Molar Mass: 82.03 g/mol: Density: 1.528 g/cm 3: Boiling Point: 881.4☌: Melting Point: 324☌: Chemical Properties of Sodium Acetate. Therefore, the total mass of the reactants wil beĪccording to the law of mass conservation, the total mass of the products must be equal to the total mass of the reactants., which means that If the solubility of sodium acetate (Molar mass 82 g/mol) is 76 grams per 100 grams of water, which of the following solutions would be considered supersaturated 5. #8.4cancel("g") * ("1 mole "NaHCO_3)/(84.007cancel("g")) ~= "0.10 moles "#NaHCO_3#Īccording to the #1:1# mole ratio that exists between sodium bicarbonate, acetic acid, and carbon dioxide, the number of moles of acetic acid that reacted is To do this, use the compounds' molar masses to calculate how many moles of each you have The first thing you need is work backwards from the mass of #CO_2# produced to determine what is the mass of acetic acid that reacted. So, you've got 8.4 g of sodium bicarbonate reacting with 20g of acetic acid, and producing 4.4 g of carbon dioxide. The carbonic acid will then decompose to give water and carbon dioxide, #CO_2#. Solution For Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of0.375 molar aqueous solution. Koh density.Sodium bicarbonate, #NaHCO_3#, and acetic acid, #CH_3COOH#, will react to produce sodium acetate, #CH_3COONa#, and carbonic acid, #H_2CO_3#.
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